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Webdispo S.A.R.L.'s picture
Asked by on Fri 23rd Oct 2009
Showing view results depending on URL

Hi all,

I wanted to show results of a view depending on URL.

I explain :

I have content type named “car”, with one field named “gallery”.

I add a view named “view_galerie”, this view must show the gallery of a car depending on URL.

Example : if the user enter the node /mysite/cars/aston-martin-db9, the view will show the gallery of the aston martin db9.

I know that i must use the views arguments to do that, but i think that i need a php snippet code.

Thanks for your precious help

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